парсинг xml в java

[SkrudjMakdak]

Вот код:

package com.app;

import java.io.IOException;
import java.io.StringReader;
import java.util.HashMap;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;

import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

public class Xml
	{
	private String xml = ""
	+ "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"
	+ "<application>"
		+ "<class name = \"MainClass\">"
			+ "<method name = \"main\"/>"
		+ "</class>"
		+ "<class name = \"Window\">"
			+ "<method name = \"open\"/>"
			+ "<method name = \"close\"/>"
			+ "<method name = \"show\"/>"
			+ "<method name = \"hide\"/>"
		+ "</class>"
		+ "<class name = \"DataBase\">"
			+ "<method name = \"connect\"/>"
			+ "<method name = \"disconnect\"/>"
			+ "<method name = \"getData\"/>"
		+ "</class>"
	+ "</application>";
	
	public void gx()
		{
		DocumentBuilderFactory f = DocumentBuilderFactory.newInstance();
		//f.setValidating(false);
		DocumentBuilder builder;
		try
			{
			builder = f.newDocumentBuilder();
			Document doc = builder.parse(new InputSource(new StringReader(xml)));
			Node node = doc.getFirstChild();
			String text = node.getNodeValue();
			System.out.print(text);
			}
		catch (ParserConfigurationException e)
			{
			System.out.print("1");
			}
		catch (SAXException e)
			{
			System.out.print("2");
			}
		catch (IOException e)
			{
			e.printStackTrace();
			}
		
		}
	}

почему выводит null? как вывести результат?