Файл

[Seferus]

#include "stdafx.h"
#include <iostream>
#include <stdio.h>
#include <conio.h>
#include <string.h>
using namespace std;


int _tmain(int argc, _TCHAR* argv[])
{
char ch=' ';
do{ 

FILE*f; f = fopen ("D:\\Bolee5.txt", "wt");
FILE*d; d = fopen ("D:\\Menee5.txt", "wt");
FILE*c; c = fopen ("D:\\Bolee30.txt", "wt");
FILE*e; e = fopen ("D:\\Bolee30.txt", "r");
FILE*g; g = fopen ("D:\\Bolee5.txt", "r");
FILE*h; h = fopen ("D:\\Menee5.txt", "r");


int a;
char str [50];

printf( " Ves v kg:   ");

scanf ( "%d", &a);
if(a<5)
printf( "Vam podhodit Tu-134\n\n");
fprintf(f, "Tu-134");
if(a>5 && a<30)
printf( "Vam podhodit Il-86\n\n");
fprintf(d,"Il 86" );
if(a>30)
printf( "Vam podhodit Rusik\n\n");
fprintf(c,"Rusik" );
fclose(c);fclose(d);fclose(f);


fgets(str,30,e);

printf("Esli ves bolee 30 to %s\n",str);

fgets(str,30,g);

printf("Esli ves mezhdu 5 i 30 to %s\n",str);

fgets(str,30,h);
printf("Esli ves menee 5 to %s",str);

cout<<"\n\nChoose: Press [f] to exit or [r] to repeat - "; 
ch=getch();
cout<<"\n";
}
	while (ch!='f');
			getch();
		return 0;

}

как сделать чтобы был один файл?

[kaljan775]

заменить

FILE*f; f = fopen ("D:\\Bolee5.txt", "wt");
FILE*d; d = fopen ("D:\\Menee5.txt", "wt");
FILE*c; c = fopen ("D:\\Bolee30.txt", "wt");
FILE*e; e = fopen ("D:\\Bolee30.txt", "r");
FILE*g; g = fopen ("D:\\Bolee5.txt", "r");
FILE*h; h = fopen ("D:\\Menee5.txt", "r");

на

FILE*f; f = fopen ("D:\\Bolee5.txt", "wt");
FILE*h; h = fopen ("D:\\Menee5.txt", "r");

может так ? )

[Seferus]

сп большое

[kaljan775]

просто неясен вопрос )