Преобразование в обратную польскую запись с++

[sobaka13]

BDA,

 int main()
{
    system("chcp 1251>nul");
    stack* poland = nullptr;
    char expression[100];
    char source_line[100];
    int i = 0, j = 0;
    cout << "Input expression: ";
    cin.getline(expression, 100);
    try
    {
        while (expression[i] != '\0')
        {
            if (isNumber(expression[i]))
            {
                source_line[j++] = expression[i];
            }
            if (isOpenBracket(expression[i]))
            {
                push(poland, expression[i]);
            }
            if (isClosingBracket(expression[i]))
            {
                int k = pop(poland);
                while (!isPairedBracket(k, expression[i]))
                {
                    source_line[j++] = ' ';
                    source_line[j++] = k;
                    k = pop(poland);
                }
            }
            if (isOperation(expression[i]))
            {
                source_line[j++] = ' ';
                while (poland && prior(peek(poland)) >= prior(expression[i]))
                {
                    source_line[j++] = pop(poland);
                    source_line[j++] = ' ';
                }
                push(poland, expression[i]);
            }
            i++;
        }
        while (poland)
        {
            source_line[j++] = ' ';
            source_line[j++] = pop(poland);
        }
        source_line[j] = '\0';
        cout << source_line;
    }
    catch (exception e)
    {
        source_line[j] = '\0';
        cout << source_line << e.what() << endl;
    }
    system("pause>nul");
    return 0;
}

[sobaka13]

вроде работает

[BDA]

Да, похоже на правду. Если строка будет корректной, то сработает.